So, on the Firebolt question - the vt graph should be a straight line, Randall put me to it. At first I didn't think so, because I thought the acceleration would be changing, because I thought the force applied to make it go would be changing, but my mum made me realise that we could just apply a constant force throughout for a constant acceleration (which is probably what happens) and therefore have a straight vt graph.

Therefore!

area under vt graph
= 0.5 X 10 X 67.04
= 335.2

So, a Firebolt will travel 335.2m in the first 10 seconds. This means that during this time,

average speed of Firebolt
= (335.2/10) m/s
= 33.52 m/s
= 0.03352 km/s
= 120.672 km/h

Which is pretty fast.

Also, at 67.04 m/s (which is 150mph), the Firebolt will be travelling at 0.06704 km/s = 241.344 km/h. Which is really, really fast.

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Central should buy Drew Carey's Green Screen because it is funky and funny and cool and they should replace Kath and Kim (the "comedy" that replaced The Kumars At No. 42) with it because Kath and Kim is really bad.

--

You know, I don't know what I want to do any more. I used to. Not specifically, but I knew where I wanted to go and what to do in general but I don't any more.

There's this... something that I would love to do, but it's so hard and I can't talk to anyone about it because I'm afraid they'd say I won't make it.

Also, I'm worried I annoy people.